Solved Problem 03 | Rectangular Parallelepiped

Volume of the pile
$V_{pile} = 7(36)(12)$

$V_{pile} = 3024 \, \text{ ft}^3$
 

Volume of one brick
$V_{brick} = \dfrac{2}{12} \left( \dfrac{4}{12} \right)\left( \dfrac{9}{12} \right)$

$V_{brick} = \dfrac{1}{24} \, \text{ ft}^3$
 

Number of bricks in the pile

$= \dfrac{V_{pile}}{V_{brick}}$

$= \dfrac{3024}{\frac{1}{24}}$

$= 72\,576 \, \text{ bricks}$           answer