Problem 513 In Fig. P-512, the homogeneous block weighs 300 kg and the coefficient of friction is 0.45. If h = 50 cm, determine the force P to cause motion to impend.
Solution 513
$N = 300 \cos \theta = 300(\frac{4}{5})$
$N = 240 \, \text{ kg}$
$f = \mu N = 0.45(240)$
$f = 108 \, \text{ kg}$
$\Sigma F_x = 0$
$P + f = 300 \sin \theta$
$P + 108 = 300(\frac{3}{5})$
$P = 72 \, \text{ kg}$ answer
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