
$a = 10 \cos 60^\circ = 5 \, \text{ cm}$
$b = 10 - a = 5 \, \text{ cm}$
$\Sigma M_A = 0$
$Pb = W_{cyl}a$
$P(5) = 10(5)$
$P = 10 \, \text{ kN}$ answer
$\Sigma M_O = 0$
$10f = 10P$
$f = P$
$f = 10 \, \text{ kN}$
$\Sigma F_y = 0$
$N = 10 \cos 30^\circ + P \cos 30^\circ$
$N = 10 \cos 30^\circ + 10 \cos 30^\circ$
$N = 17.32 \, \text{ kN}$
$f = \mu N$
$10 = \mu (17.32)$
$\mu = 0.577$ answer