Problem 543 | Friction on Wedges

$R_2 \cos 30^\circ = 200$

$R_2 = 230.94 \, \text{ kN}$
 

From the FBD of the lower wedge
$\Sigma F_V = 0$

$R_3 \cos 25^\circ = R_2 \cos 30^\circ$

$R_3 \cos 25^\circ = 230.94 \cos 30^\circ$

$R_3 = 220.68 \, \text{ kN}$
 

$\Sigma F_H = 0$

$P = R_2 \sin 30^\circ + R_3 \sin 25^\circ$

$P = 230.94 \sin 30^\circ + 220.68 \sin 25^\circ$

$P = 208.73 \, \text{ kN}$           answer