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- Principles of Statics
- Equilibrium of Force System
- Analysis of Structures
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Friction
- Problem 506 | Friction
- Problem 507 | Friction
- Problem 508 | Friction
- Problem 509 | Friction
- Problem 510 | Friction
- Problem 511 | Friction
- Problem 512 | Friction
- Problem 513 | Friction
- Problem 514 | Friction
- Problem 515 | Friction
- Problem 516 | Friction
- Problem 519 | Friction
- Problem 520 | Friction
- Problem 521 | Friction
- Problem 522 | Friction
- Problem 523 | Friction
- Problem 524 | Friction
- Problem 525 | Friction
- Problem 526 | Friction
- Problem 527 and Problem 528 | Friction
- Problem 529 | Friction
- Problem 530 | Friction
- Problem 531 | Friction
- Problem 532 | Friction
- Problem 533 | Friction
- Problem 535 | Friction on Wedges
- Problem 536 | Friction on Wedges
- Problem 537 | Friction on Wedges
- Problem 538 | Friction on Wedges
- Problem 539 | Friction on Wedges
- Problem 540 | Friction on Wedges
- Problem 541 | Friction on Wedges
- Problem 542 | Friction on Wedges
- Problem 543 | Friction on Wedges
- Problem 544 | Friction on Wedges
- Centroids and Centers of Gravity
- Moment of Inertia and Radius of Gyration
- Dynamics
- Force Systems in Space
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Hi sir. Goodmorning. Bakit po
Hi sir. Goodmorning. Bakit po pala natanggal ung normal force sa horizontal surface when the cylinder turns due to force "P" and ung normal force sa may inclined surface ay hinde? I was thinking about the cylinder would be on the same spot po pa rin kasi if turned by a force "P" since angle of friction=tan-1(0.3)= 17° is lesser than the angle of the inclined plane.