The plank impends to the right
$\dfrac{R_B}{\sin 25^\circ} = \dfrac{P}{\sin 105^\circ}$
$R_B = 0.4375P$
$\Sigma M_A = 0$
$Px = (R_B \cos 50^\circ)(10)$
$Px = (0.4375P \cos 50^\circ)(10)$
$x = 2.81 \, \text{ ft}$ answer
The plank impends to the left
$\dfrac{R_A}{\sin 10^\circ} = \dfrac{P}{\sin 105^\circ}$
$R_A = 0.1798P$
$\Sigma M_B= 0$
$Py = (R_A \cos 65^\circ)(10)$
$Py = (0.1798P \cos 65^\circ)(10)$
$y = 0.76 \, \text{ ft}$ answer