015 Two unequal balls inside the cylinder

$x = 7.5 \, \text{ cm}$
 

$h^2 + x^2 = (5 + 7.5)^2$

$h^2 + 7.5^2 = 12.5^2$

$h = 10 \, \text{ cm}$
 

Depth of water
$H = 7.5 + h + 5$

$H = 7.5 + 10 + 5$

$H = 22.5 \, \text{ cm}$
 

Volume of water
$V_{water} = V_H - V_{balls}$

$V_{water} = \frac{1}{4}\pi (20^2)(22.5) - \frac{4}{3}\pi (7.5^3 + 5^3)$

$V_{water} = 4777.84 \, \text{ cm}^3$           answer