012 Sphere circumscribed about a right circular cylinder

Diameter of the sphere
$D^2 = 6^2 + 6^2$

$D = 6\sqrt{2} \, \text{ in}$
 

Volume of the sphere:
$V = \frac{1}{6}\pi D^3 = \frac{1}{6}\pi (6\sqrt{2})^3$

$V = 319.89 \, \text{ in}^3$           answer
 

Total surface area of the sphere:
$A = \pi D^2 = \pi (6\sqrt{2})^2$

$A = 226.19 \, \text{ in}^2$           answer