MSTE Refresher Lite

MSTE - Mathematics, Surveying and Transportation Engineering
Review Instructor: Jhun Vert
Language: Taglish, more on Tagalog
 

Get yourself acquainted with the CE board exam problems in MSTE. Experience the level of difficulty you will encounter in the actual board examination and feel the similar time-constraint in solving problems. Learn how to solve the problem in the most efficient way and improve your problem solving strategies from experienced CE review instructor.
 

MATHalino Launches New Online Courses

This is not a promotional post. This is about my experience in building the platform for online courses.
online-course.jpg

 

Creating an online course is monumental, especially for a small website like MATHalino. Despite being managed by only one person from the ground up, the development of this functionality has been progressing gradually. I have been conceiving this feature for as long as I can remember, even before online courses became common in the Philippines.

What prevented me from implementing it earlier came down to three factors.

Basic Algebra Review

Is this course right for you?
Although we named this course Basic Algebra Review, this is actually designed for those who already completed their Algebra subject in engineering curriculum, hence, review. Problems presented in later topics are not really for beginners and solutions presented here assumed that you already earned the credits of College Algebra from your university.

Beginners however are also welcome to join, but never consider this course as a substitute to the long standing and thoroughly tested university program. Don't forget that your professor is the one holding the authority of the subject. Whenever contradiction arises between my teaching and that of your professor, do not follow me, listen to your professor. You may consider this course, however, as a supplement material to the already rich Algebra materials handed to you in your school.
 

Situation
The three-hinged arch shown below is loaded with symmetrically placed concentrated loads as shown in the figure below.
 

2015-may-design-three-hinged-arch-given.png

 

The loads are as follows:
$$P_1 = 90 ~ \text{kN} \qquad P_2 = 240 ~ \text{kN}$$
 

The dimensions are:
$$H = 8 ~ \text{m} \qquad S = 4 ~ \text{kN}$$
 

Calculate the following:
 

1.   The horizontal reaction at A.

A.   0 C.   330 kN
B.   285 kN D.   436 kN

2.   The total reaction at B.

A.   0 C.   330 kN
B.   285 kN D.   436 kN

3.   The vertical reaction at C.

A.   0 C.   330 kN
B.   285 kN D.   436 kN