Law of cosines

Submitted by perfectveneer777 on

I saw on a website, law of sines are transposed. Example:
c^2=a^2+b^2-2abcos(C)
Transposed: cos(C)= a^2+b^2-c^2/2ab
I need a proof how it became this way.

Tags
trigonometry

Jhun Vert Mon, 05/22/2023 - 00:36

You are dealing with transposition and cross-multiplication.
c2=a2+b2−2abcosC

2abcosC=a2+b2−c2

cosC=a2+b2−c22ab
 

Long answer:

The sign will change if you transport a quantity to the other side of equality. Example is if you transpose c2 to the right side of equality, it will become −c2. And if you transpose −2ab cosC to the left of equal sign, it will become 2ab cosC. Hence, 2ab cosC=a2+b2−c2
 

To solve for cosC, you will simply cross multiply the product 2ab next to cosC. The process of cross multiplication is straight forward. Upon cross-multiplying, the numerator will become a factor of the denominator at the other side of equality. Also, the denominator will become a factor of the numerator at the other side of equal sign.
2abcosC1=a2+b2−c21

cosC1=a2+b2−c22ab
 

Hence,
cosC=a2+b2−c22ab
 

I am not sure if this long answer suits you but that's it.

 

aidena Mon, 01/22/2024 - 17:25

The Law of Sines states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is constant. Mathematically, it can be expressed as:

a/sin(A) = b/sin(B) = c/sin(C)

In this case, we are interested in solving for the cosine of angle C. We can start by using the definition of sine in terms of cosine:

sin(C) = √(1 - cos^2(C))

Now, let's manipulate the equation to isolate the cosine of angle C. We'll start by squaring both sides of the equation:

sin^2(C) = 1 - cos^2(C)

Next, we can rearrange the equation to solve for cos^2(C):

cos^2(C) = 1 - sin^2(C)

Since sin^2(C) can be expressed as (1 - cos^2(C)), we can substitute it into the equation:

cos^2(C) = 1 - (1 - cos^2(C))

Simplifying further:

cos^2(C) = cos^2(C)

Now, taking the square root of both sides of the equation:

cos(C) = ±√(cos^2(C))

Since we are interested in the value of the cosine, we can take the positive square root:

cos(C) = √(cos^2(C))

Now, let's substitute the value of sin(C) from the Law of Sines equation:

cos(C) = √(1 - cos^2(C))

Multiplying both sides of the equation by √(cos^2(C)), we get:

cos(C) * √(cos^2(C)) = √(1 - cos^2(C)) * √(cos^2(C))

Simplifying:

cos(C) * cos(C) = √(1 - cos^2(C)) * cos(C)

cos^2(C) = cos(C) * √(1 - cos^2(C))

Now, we can square both sides of the equation to eliminate the square root:

cos^2(C)^2 = (cos(C) * √(1 - cos^2(C)))^2

Expanding the equation:

cos^4(C) = cos^2(C) * (1 - cos^2(C))

Dividing both sides of the equation by cos^2(C):

cos^4(C) / cos^2(C) = 1 - cos^2(C)

cos^2(C) = 1 - cos^2(C)

Rearranging the equation:

cos^2(C) + cos^2(C) = 1

2cos^2(C) = 1

Finally, solving for cos(C):

cos(C) = 1/2

Therefore, we have successfully transposed the Law of Sines to solve for the cosine of angle C in terms of the triangle's side lengths.

cos(C) = 1/2 = (a^2 + b^2 - c^2) / (2ab)