From the FBD of 1000 lb block
$\Sigma F_V = 0$
$2(R_1 \cos 25^\circ) = 1000$
$R_1 = 551.69 \, \text{ lb}$
From the FBD of any of the wedges
$\Sigma F_V = 0$
$R_2 \cos 10^\circ = R_1 \cos 25^\circ$
$R_2 \cos 10^\circ = 551.69 \cos 25^\circ$
$R_2 = 507.71 \, \text{ lb}$
$\Sigma F_H = 0$
$P = R_1 \sin 25^\circ + R_2 \sin 10^\circ$
$P = 551.69 \sin 25^\circ + 507.71 \sin 10^\circ$
$P = 321.32 \, \text{ lb}$ answer