Differential Equation: $ye^{xy} dx + xe^{xy} dy = 0$
Please help me to solve this differential equation
yexydx+xexydy=0
Differential Equation
Differential Equations: $(r - 3s - 7) dr = (2r - 4s - 10) ds$
The topic is Additional Topics in Ordinary DE of the first order.
(r-3s-7)dr=(2r-4s-10)ds
Differential Equations: $(x - 2y - 1) dy = (2x - 4y - 5) dx$
Coefficient Linear in Two Variables? Help please.
(x-2y-1)dy=(2x-4y-5)dx
DIIFERENTIAL EQUATION: $(x^2 + y^2) dx + x (3x^2 - 5y^2) dy = 0$
( x^2 + y^2 ) dx + x (3x^2 - 5y^2 ) dy = 0
DE: $x \, dx + [ sin^2 (y/x) ](y \, dx - x \, dy) = 0$
xdx + sin^2 ( y/x ) [ ydx - xdy ] = 0
Differential EQNS: $y \, dx = \left[ x + (y^2 - x^2)^{1/2} \right] dy$
ydx = x + √ y^2 - x^2 dy
differential equations: $y(9x - 2y)dx - x(6x - y)dy = 0$
y(9x -2y)dx - x(6x - y) dy = 0
Differential Equations: $[x \csc (y/x) - y] dx + x \, dy = 0$
2. (x csc y/x - y) dx + xdy=0
3. (x^2 + 2xy - 4y^2) dx - ( x^2 - 8xy - 4 y^2)=0
4. x^y ' = 4x^2 + 7xy + 2 y^2
Differential Equations: $(6x-3y+2)dx - (2x-y-1)dy = 0$
Help a stranger please. This is for my homework and I'm having a hard time solving these equations. Show the complete solutions and final answers please. It will be a great help. Thank you so much.
This covers Additional Topics on Equations of Order One, Coefficient Linear in Two Variables.
1. (6x-3y+2)dx-(2x-y-1)dy=0
2. (x+2y-1)dx-(2x+y-5)dy=0
Elimination of arbitrary constants: $y = Ae^{ax} \cos (bx) + Be^{ax} \sin (bx)$
Im having a difficulty solving this problem y = Aeaxcos(bx)+Beaxsin(bx) where a and b are parameters. Can anyone show me how to solve this ?
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