Sydney Sales

Member for

8 years 4 months

My Questions

DE: $(x²+4) y' + 3 xy = x$

bernoullis equation

particular soln.

bernoulli: $(y^4 - 2xy) dx + 3 x^2 dy= 0$

engineering economy

DE exact equations: (3 + y + 2y^2 sin^2 x) dx + (x + 2xy - y sin 2x) dy = 0

DE Order one: (xy^2 + x - 2y + 3) dx + x^2 ydy = 2(x + y) dy

equations of order one: (1 - xy)^2 dx + [ y^2 + x^2 (1 - xy)^(-2) ] dy = 0

DE: 2xy dx + (y^2 - x^2) dy = 0

DE: 2xy dx + (y^2 + x^2) dy = 0

exact DE: [ 2x + y cos (x^2) - 2xy + 1 ] dx + [ sin (x^2) - x^2 ] dy = 0

DIIFERENTIAL EQUATION: $(x^2 + y^2) dx + x (3x^2 - 5y^2) dy = 0$

DE: $x \, dx + [ sin^2 (y/x) ](y \, dx - x \, dy) = 0$

Differential EQNS: $y \, dx = \left[ x + (y^2 - x^2)^{1/2} \right] dy$

differential equations: $y(9x - 2y)dx - x(6x - y)dy = 0$

Differential Equations: $[x \csc (y/x) - y] dx + x \, dy = 0$

HOMOGENEOUS DE: $(x - y \ln y + y \ln x) dx + x(\ln y - \ln x) dy = 0$

MIGRATED: interest and compound: A man wishes his son to receive P200,000 ten years from now

interest and compound: amount of loan payment

My Answers

i need a solution

that is a differential

what will be the solution.

eto po yung answer:

meron po. kaso pano po pag

sa factoring po. bakit po

ydx = [x + ( y^2 - x^2 )^ 1/2

ydx= x + ( y^2 - x^2) ^ 1/2

bakit po naging

parang ganito po yung factor

thanks po sa solution.. yung

pano po ung problem 2,3,4 for

how about the problem no.2,3