# DE

( 2x³ - y⁴) dx + xy³ dy= 0

### We can solve that the

We can solve that the integrating factor is $x^{-5}$ which gives the general solution

$-\dfrac{2}{x} + \dfrac{y^4}{4x^4} = C$

which simplifies to $\boxed{y^4 = 8x^3 + Cx^4}$

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