DE
( 2x³ - y⁴) dx + xy³ dy= 0
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We can solve that the
We can solve that the integrating factor is $x^{-5}$ which gives the general solution
$-\dfrac{2}{x} + \dfrac{y^4}{4x^4} = C$
which simplifies to $\boxed{y^4 = 8x^3 + Cx^4}$