# bernoulli: $(y^4 - 2xy) dx + 3 x^2 dy= 0$

(y^4 - 2xy) dx + 3 x^2 dy= 0

- Log in to post comments

(y^4 - 2xy) dx + 3 x^2 dy= 0

- Log in to post comments

All trademarks and copyrights on this page are owned by their respective owners. Forum posts are owned by the individual posters.

## $x^2=xy^3+Cy^3$

$x^2=xy^3+Cy^3$

## what will be the solution.

In reply to $x^2=xy^3+Cy^3$ by Infinitesimal

what will be the solution.