Differential Equation: $(1-xy)^{-2} dx + \left[ y^2 + x^2 (1-xy)^{-2} \right] dy = 0$
Hello, can anyone solve this equation?
I can't figure it out,
$(1-xy)^{-2} dx + \left[ y^2 + x^2 (1-xy)^{-2} \right] dy = 0$
Thanks.
Differential Equation
DE: $(x²+4) y' + 3 xy = x$
(x²+4) y' + 3 xy = x
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bernoulli: $(y^4 - 2xy) dx + 3 x^2 dy= 0$
(y^4 - 2xy) dx + 3 x^2 dy= 0
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Differential Equation $2y \, dx+x(x^2 \ln y -1) \, dy = 0$
Please help me solve this Differential Equation
2ydx+x(x2lny -1)dy=0
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differential equation: Determine whether a member of the family can be found that satisfies the initial conditions
The given two-parameter family is a solution of the indicated differential equation on the
interval (−∞,∞). Determine whether a member of the family can be found that satisfies the
initial conditions.
y = c1e^x cos x + c2e^x sin x; y" − 2y' + 2y = 0,
i. y(0) = 1, y'(π) = 0
ii. y(0) = 1, y(π) = −1