Differential Equation: $ye^{xy} dx + xe^{xy} dy = 0$
Please help me to solve this differential equation
yexydx+xexydy=0
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$ye^{xy}\,dx + xe^{xy}\,dy =
$ye^{xy}\,dx + xe^{xy}\,dy = 0$
$e^{xy}(y\,dx + x\,dy) = 0$
$e^{xy} \, d(xy) = 0$
$\displaystyle \int e^{xy} \, d(xy) = 0$
$e^{xy} = c$ answer
Than you sir Romel. God bless
In reply to $ye^{xy}\,dx + xe^{xy}\,dy = by Jhun Vert
So it was not an exact equation haha. By the way thank you sir Romel. God bless.
Boss pahelp naman po...
Boss pahelp naman po....pleassssssss sir.....
1. (2ycosx + sin⁴x)dx = sin x dy when x=½π, y=1
2. (1+4xy-4x²y) dx +(x²-x³)dy =0 when x=2, y=¼