By symmetry:
$R_1 = R_2 = \frac{1}{2}(\frac{1}{2}Lw_o) = \frac{1}{4}Lw_o$
$\dfrac{y}{x} = \dfrac{w_o}{L/2}$
$y = \dfrac{2w_o}{L}x$
$F = \frac{1}{2}xy = \frac{1}{2}x \left( \dfrac{2w_o}{L} \right)$
$F = \dfrac{w_o}{L}x^2$
$V = R_1 - F$
$V = \frac{1}{4}Lw_o - \dfrac{w_o}{L}x^2$
$M = R_1x - F(\frac{1}{3}x)$
$M = \frac{1}{4}Lw_ox - \left( \dfrac{w_o}{L}x^2 \right)(\frac{1}{3}x)$
To draw the Shear Diagram:
V = Lw_{o}/4 - w_{o}x^{2}/L is a second degree curve; at x = 0, V = Lw_{o}/4; at x = L/2, V = 0. The other half of the diagram can be drawn by the concept of symmetry.
To draw the Moment Diagram
M = Lw_{o}x/4 - w_{o}x_{3}/3L is a third degree curve; at x = 0, M = 0; at x = L/2, M = L_{2}w_{o}/12. The other half of the diagram can be drawn by the concept of symmetry.