Problem 814 | Continuous Beam by Three-Moment Equation

$L_1 = L_2 = 10 \, \text{ ft}$
 

$\dfrac{6A_1\bar{a}_1}{L_1} = \dfrac{7w_oL^3}{60} + \dfrac{8w_oL^3}{60} = \dfrac{7(200)(10^3)}{60} + \dfrac{8(100)(10^3)}{60}$

$\dfrac{6A_1\bar{a}_1}{L_1} = 36\,666.67 \, \text{ lb}\cdot\text{ft}^2$
 

$\dfrac{6A_2\bar{b}_2}{L_2} = \dfrac{8w_oL^3}{60} = \dfrac{8(100)(10^3)}{60}$

$\dfrac{6A_2\bar{b}_2}{L_2} = 13\,333.33 \, \text{ lb}\cdot\text{ft}^2$