# three-moment equation factors

## Problem 822 | Continuous Beam by Three-Moment Equation

**Problem 822**

Solve Prob. 821 if the concentrated load is replaced by a uniformly distributed load of intensity w_{o} over the middle span.

Answers:

$M_2 = -\dfrac{w_o L^2}{4} \cdot \dfrac{1 + 2\beta}{4(\alpha + 1)(1 + \beta) - 1}$

$M_3 = -\dfrac{w_o L^2}{4} \cdot \dfrac{1 + 2\alpha}{4(1 + \alpha)(1 + \beta) - 1}$

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## Problem 821 | Continuous Beam by Three-Moment Equation

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## Problem 820 | Continuous Beam by Three-Moment Equation

**Problem 820**

Solve Prob. 819 if the concentrated load is replaced by a uniformly distributed load of intensity w_{o} over the first span.

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## Problem 819 | Continuous Beam by Three-Moment Equation

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## Problem 818 | Continuous Beam by Three-Moment Equation

**Problem 818**

In Problem 817, determine the changed value of the applied couple that will cause M_{2} to become zero.

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## Problem 817 | Continuous Beam by Three-Moment Equation

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## Problem 816 | Continuous Beam by Three-Moment Equation

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## Problem 815 | Continuous Beam by Three-Moment Equation

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## Problem 814 | Continuous Beam by Three-Moment Equation

**Problem 814**

Find the moment at R_{2} of the continuous beam shown in Fig. P-814.

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## Problem 813 | Continuous Beam by Three-Moment Equation

**Problem 813**

Determine the moment over the support R_{2} of the beam shown in Fig. P-813.

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