Solution to Problem 694-695 | Beam Deflection by Method of Superposition

$\delta_v = a\theta + \delta$

$\delta_v = a\left( \dfrac{Mb}{EI} \right) + \dfrac{Ma^2}{2EI}$

$\delta_v = \dfrac{Mba}{EI} + \dfrac{Ma^2}{2EI}$

$\delta_v = \dfrac{Ma}{2EI}(2b + a)$           answer

$\delta_v = a\theta + \delta$

$\delta_v = a\left( \dfrac{Pab}{EI} \right) + \dfrac{Pa^3}{3EI}$

$\delta_v = \dfrac{Pa^2b}{EI} + \dfrac{Pa^3}{3EI}$

$\delta_v = \dfrac{Pa^2}{3EI}(3b + a)$           answer