concentrated load

Situation
In the figure shown, each plank carries a uniform load of 100 N/m throughout its length. The supports are on the same plane.
 

1. Find the reaction at A.
   A. 900 N
   B. 800 N
   C. 1400 N
   D. 2400 N
    
2. Find the reaction at B.
   A. 900 N
   B. 800 N
   C. 1400 N
   D. 2400 N
    
3. Find the reaction at C.
   A. 900 N
   B. 800 N
   C. 1400 N
   D. 2400 N
    

Problem 855
If the distributed load in Prob. 854 is replaced by a concentrated load P at midspan, determine the moments over the supports.
 

Answers:
$M_1 = \dfrac{PL}{8} \cdot \dfrac{1}{\alpha + 2} = M_4$

$M_2 = -\dfrac{PL}{8} \cdot \dfrac{2}{\alpha + 2} = M_3$
 

Problem 853
For the continuous beam shown in Fig. P-853, determine the moment over the supports. Also draw the shear diagram and compute the maximum positive bending moment. (Hint: Take advantage of symmetry.)
 

Problem 852
Find the moments over the supports for the continuous beam in Figure P-852. Use the results of Problems 850 and 851.
 

Answers
$M_1 = -146.43 ~ \text{N}\cdot\text{m}$

$M_2 = -307.14 ~ \text{N}\cdot\text{m}$

$M_3 = -521.43 ~ \text{N}\cdot\text{m}$
 

Problem 851
Replace the distributed load in Problem 850 by a concentrated load P at the midspan and solve for the moment over the supports.
 

Problem 847
Compute the moments over the supports and sketch the shear diagram for the continuous beam shown in Fig. P-847.
 

Problem 845
Compute the moments over the supports for the beam shown in Fig. P-845 and then draw the shear diagram.
 

Problem 844
In the propped beam shown in Fig. P-844, determine the prop reaction.
 

Problem 834
Refer to Problem 826.
 

Problem 833
Refer to Problem 825 for which M₂ = -980 lb·ft and M₃ = -1082 lb·ft.