# Quadrilateral Circumscribing a Circle

Quadrilateral circumscribing a circle (also called tangential quadrilateral) is a quadrangle whose sides are tangent to a circle inside it.

Area,

$A = rs$

Where *r* = radius of inscribed circle and *s* = semi-perimeter = (*a* + *b* + *c* + *d*)/2

**Derivation for area**

Let *O* and *r* be the center and radius of the inscribed circle, respectively.

$A_{AOB} = \frac{1}{2}ar$

$A_{BOC} = \frac{1}{2}br$

$A_{COD} = \frac{1}{2}cr$

$A_{AOD} = \frac{1}{2}dr$

Total area

$A = A_{AOB} + A_{BOC} + A_{COD} + A_{AOD}$

$A = \frac{1}{2}ar + \frac{1}{2}br + \frac{1}{2}cr + \frac{1}{2}dr$

$A = \frac{1}{2}(a + b + c + d)r$

$A = sr$ (*okay!*)

**Some known properties**

- Opposite sides subtend supplementary angles at the center of inscribed circle. From the figure above, ∠
*AOB*+ ∠*COD*= 180° and ∠*AOD*+ ∠*BOC*= 180°. - The area can be divided into four kites. See figure below.

- If the opposite angles are equal (
*A*=*C*and*B*=*D*), it is a rhombus.