$x = 5 \cos 37^\circ = 4 \, \text{ m}$
$y = 5 \sin 37^\circ = 3 \, \text{ m}$
$\Sigma M_A = 0$
$6(\frac{4}{5}T) = 2(100) + 6(800)$
$T = 1041.67 \, \text{ kN}$ answer
$\Sigma M_E = 0$
$6A_H = 2(100) + 6(800)$
$A_H = 833.33 \, \text{ kN}$ answer
$\Sigma F_V = 0$
$A_V + \frac{3}{5}T = 100 + 800$
$A_V + \frac{3}{5}(1041.67) = 900$
$A_V = 275 \, \text{ kN}$ answer
From FBD of member ABC
$\Sigma M_A = 0$
$6(\frac{3}{\sqrt{13}}F_{CD}) = 2(100) + 6(800)$
$F_{CD} = 1001.54$ answer