$\Sigma M_B = 0$
$24(\frac{2}{\sqrt{13}}T) = 12\,000(10 \sin 53^\circ)$
$T = 7198.80 \, \text{ lb}$
$\Sigma F_H = 0$
$B_H = \frac{2}{\sqrt{13}}T$
$B_H = \frac{2}{\sqrt{13}}(7198.81)$
$B_H = 3993.18 \, \text{ lb}$ answer
$\Sigma F_V = 0$
$B_V = \frac{3}{\sqrt{13}}T + 12\,000$
$B_V = 17 989.77 \, \text{ lb}$ answer