a=12cos60∘=6 ft
b=12sin60∘=6√3 ft
c=8sin60∘=4√3 ft
d=btan37∘=6√3tan37∘ ft
ΣMA=0
12Tn=10000c+8000b
12(Tsin67∘)=10000(4√3)+8000(6√3)
T=13798.63 lb answer
ΣMD=0
AH(a+d)=10000c+8000b
AH(6+6√3tan37∘)=10000(4√3)+8000(6√3)
AH=11020.08 lb answer
ΣFV=0
AV+Tsin37∘=10000+8000
AV+13798.63sin37∘=10000+8000
AV=9695.78 lb answer