$\Sigma F_V = 0$
$A_v = 10.8 \, \text{ kN}$
The given load and AV produce a counterclockwise couple
$C = 1.8(10.8)$
$C = 19.44 \, \text{ kN}\cdot\text{m counterclockwise}$
$\Sigma F_H = 0$
$B_h = A_h$
Since Bh = Ah, the two are clockwise couple.
$C_{counterclockwise} = C_{clockwise}$
$19.44 = 1.2B_h$
$B_h = 16.2 \, \text{ kN}$
Thus,
$A_h = 16.2 \, \text{ kN}$
Summary (answer)
$A_v = 10.8 \, \text{ kN upward}$
$A_h = 16.2 \, \text{ kN to the left}$
$B_h = 16.2 \, \text{ kN to the right}$