# Components of a Force

Forces acting at some angle from the the coordinate axes can be resolved into mutually perpendicular forces called *components*. The component of a force parallel to the x-axis is called the x-component, parallel to y-axis the y-component, and so on.

**Components of a Force in XY Plane**

$F_x = F \cos \theta_x = F \sin \theta_y$

$F_y = F \sin \theta_x = F \cos \theta_y$

$F= \sqrt{{F_x}^2 + {F_y}^2}$

$\tan \theta_x = \dfrac{F_y}{F_x}$

Given the slope of the line of action of the force as *v*/*h*

$r =\sqrt{h^2 + v^2}$

$F_x = F (h/r)$

$F_y = F (v/r)$

**Components of a Force in 3D Space**

Given the *direction cosines* of the force:

$F_x = F \cos \theta_x$

$F_y = F \cos \theta_y$

$F_z = F \cos \theta_z$

$F = \sqrt{{F_x}^2 + {F_y}^2 + {F_z}^2}$

$\cos \theta_x = \dfrac{F_x}{F}$

$\cos \theta_y = \dfrac{F_y}{F}$

$\cos \theta_z = \dfrac{F_z}{F}$

Given the coordinates of any two points along the line of action of the force (with reference to the figure shown, one of the points is the origin):

Let *d* = distance *OB*

$d = \sqrt{x^2 + y^2 + z^2}$

$F_x = F (x/d)$

$F_y = F (y/d)$

$F_z = F (z/d)$

**Vector Notation of a Force (Rectangular Representation of a Force)**

Where **λ** is a unit vector. There are two cases in determining **λ**; by direction cosines and by the coordinates of any two points on the line of action of the force.

Given the direction cosines:

${\bf \lambda} = \cos \theta_x {\bf i} + \cos \theta_y {\bf j} + \cos \theta_z {\bf k}$

Given any two points *P*_{1}(*x*_{1}, *y*_{1}, *z*_{1}) and *P*_{2}(*x*_{2}, *y*_{2}, *z*_{2}) on the line of action of the force:

${\bf \lambda} = \dfrac{1}{d} \left( d_x{\bf i} + d_y {\bf j} + d_z {\bf k} \right)$

Where**i**, **j**, and **k** are unit vectors in the direction of x, y and z respectively.

$d_x = x_2 - x_1$

$d_y = y_2 - y_1$

$d_z = z_2 - z_1$

$d = \sqrt{{d_x}^2 + {d_y}^2 + {d_z}^2}$

$\cos \theta_x = d_x / d$

$\cos \theta_y = d_y / d$

$\cos \theta_z = d_z / d$

Note:

$\cos^2 \theta_x + \cos^2 \theta_y + \cos^2 \theta_z = 1$

$(d_x / d)^2 + (d_y / d)^2 + (d_z / d)^2 = 1$

Also note the following:

$F_x = \cos \theta_x = d_x / d$

$F_y = \cos \theta_y = d_y / d$

$F_z = \cos \theta_z = d_z / d$

$F = \sqrt{{F_x}^2 + {F_y}^2 + {F_z}^2}$

Thus,

${\bf F} = \dfrac{F}{d} \left( d_x{\bf i} + d_y {\bf j} + d_z {\bf k} \right)$

In simplest term

The above rectangular representation of a force is applicable in both 2D and 3D forces.

- Add new comment
- 261324 reads