010 Components of force normal and tangent to hypotenuse of a triangle Problem 010 The triangular block shown in Fig. P-010 is subjected to the loads P = 1600 lb and F = 600 lb. If AB = 8 in. and BC = 6 in., resolve each load into components normal and tangential to AC. Solution 010 Click here to expand or collapse this section $F_n = F \sin \theta = 600(3/5)$ $F_n = 360 \, \text{ lb}$ $F_t = F \cos \theta = 600(4/5)$ $F_t = 480 \text{ lb}$ $P_n = P \cos \theta = 1600(4/5)$ $P_n = 1280 \, \text{ lb}$ $P_t = P \sin \theta = 1600(3/5)$ $P_t = 960 \text{ lb}$ Tags triangle parallel component perpendicular component hypotenuse normal component tangential component Triangular Block Log in or register to post comments Book traversal links for 010 Components of force normal and tangent to hypotenuse of a triangle 009 Force with given component parallel to the incline Up 016 Components of a force parallel to supporting bars