$\theta = 20^\circ + 30^\circ$

$\theta = 50^\circ$

**Perpendicular component**

$P_n = 1800 \tan \theta = 1800 \tan 50^\circ$

$P_n = 2145.16 \, \text{ N}$ *answer*

**Value of P**

$P = \dfrac{1800}{\cos \theta} = \dfrac{1800}{\cos 50^\circ}$

$P = 2800.3 \, \text{ N}$ *answer*