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 Principles of Statics
 Equilibrium of Force System
 Analysis of Structures
 Friction

Centroids and Centers of Gravity
 705 Centroid of parabolic segment by integration
 706 Centroid of quarter circle by integration
 707 Centroid of quarter ellipse by integration
 708 Centroid and area of spandrel by integration
 709 Centroid of the area bounded by one arc of sine curve and the xaxis
 714 Inverted Tsection  Centroid of Composite Figure
 715 Semicircle and Triangle  Centroid of Composite Figure
 716 Semicircular Arc and Lines  Centroid of Composite Figure
 717 Symmetrical Arcs and a Line  Centroid of Composite Line
 718 Square and Triangles  Centroid of Composite Area
 719 Closed Straight Lines  Centroid of Composite Lines
 720 Two triangles  Centroid of Composite Area
 721 Increasing the width of flange to lower the centroid of inverted Tbeam
 722 Semicircle and quarter circle  Centroid of composite area
 723 Rectangle, quarter circle and triangle  Centroid of Composite Area
 724 Rectangle, semicircle, quartercircle, and triangle  Centroid of Composite Area
 725 Centroid of windlift of airplane wing  Centroid of area
 726 Area enclosed by parabola and straigh line  Centroid of Composite Area
 Moment of Inertia and Radius of Gyration
 Dynamics
 Force Systems in Space
Recent comments
 400000=120[14π(D2−10000)]
(…1 week 6 days ago  Use integration by parts for…1 month 1 week ago
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for x2, why is it (1/2)(12)
for x2, why is it (1/2)(12) and not (2/3)(12)?
Based on the formula for
In reply to for x2, why is it (1/2)(12) by Anonymous (not verified)
Based on the formula for centroids, solving for x in an equilateral triangle will only equate to zero if it is placed along the origin. Therefore, we are just going to figure out the distance of the triangle from the origin.