Solution to Problem 510 | Flexure Formula Problem 510 A 50-mm diameter bar is used as a simply supported beam 3 m long. Determine the largest uniformly distributed load that can be applied over the right two-thirds of the beam if the flexural stress is limited to 50 MPa. Solution 510 Click here to expand or collapse this section ΣMR1=0 3R2=2w(2) R2=43w ΣMR2=0 3R1=2w(1) R1=23w (fb)max=McI Where (fb)max=50MPa M=89N⋅m c=25mm I=πr44=π(254)4 I=97656.25πmm4 50=89w(1000)(25)97656.25π w=690.29N/m Tags shear and moment diagrams simple beam Uniformly Distributed Load flexural stress bending stress Log in or register to post comments Book traversal links for Solution to Problem 510 | Flexure Formula Solution to Problem 509 | Flexure Formula Up Solution to Problem 511 | Flexure Formula