229 Y-coordinate of the point of application of the force

$400 = y_A(361)(\frac{3}{\sqrt{13}}) - 2(361)(\frac{2}{\sqrt{13}})$

$y_A = 2.665 \, \text{ ft}$           answer
 

Y-intercept of the line of action of force F
$M_O = F_xb$

$400 = 361(\frac{3}{\sqrt{13}})b$

$b = 1.332 \, \text{ ft above point O}$           answer
 

X-intercept of the line of action of force F
$M_O = F_ya$

$400 = 361(\frac{2}{\sqrt{13}})a$

$a = 1.998 \, \text{ ft to the left of point O}$           answer