- Principles of Statics
- Equilibrium of Force System
- Analysis of Structures
- Friction
- Centroids and Centers of Gravity
- Moment of Inertia and Radius of Gyration
- Dynamics
- Kinematics
- 1002 Location of warning torpedo | Rectilinear Translation
- 1003 Return in 10 seconds | Rectilinear Translation
- 1004 Relative velocity | Rectilinear Translation
- 1005 Finding the depth of well by dropping a stone | Rectilinear Translation
- 1007 Finding when and where the stones pass each other | Rectilinear Translation
- 1008 Stones thrown vertically upward | Rectilinear Translation
- 1009 Initial velocity of the second ball | Rectilinear Translation
- 1010 Time to wait in dropping a stone | Rectilinear Translation
- 1011 Time of launching a ship | Rectilinear Translation
- 1012 Train at constant deceleration | Rectilinear Translation
- 1019 Velocity and acceleration from the equation of distance | Motion with Variable Acceleration
- Two particles released from the same height and reached the base at the same time

- Curvilinear Translation (Projectile Motion)

- Kinematics
- Force Systems in Space

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## Comments

## hi.po good day.paano po

hi.po good day.paano po naging 9.47s sa time? thank you in advance po sa sasagot

## 9.47 was found by quadratic

9.47 was found by quadratic formula, I believe you get that, I think what you mean is, why use 9.47 and not 2.54 sec for

t. Using 2.54 sec fortis invalid because the second ball was shot 4 seconds after the first ball.## thank you po. na checked ko

thank you po. na checked ko na po using shft.solve