1003 Return in 10 seconds | Rectilinear Translation

$0 = v_i - 9.81(5)$

$v_i = 49.05 \, \text{ m/sec}$           answer
 

Going downward (initial velocity is zero; free-fall):
$h = \frac{1}{2}gt^2$

$h = \frac{1}{2}(9.81)(5^2)$

$h = 122.625 \, \text{ m}$           answer

$0 = v_i - 32.2(5)$

$v_i = 161 \, \text{ ft/sec}$           answer
 

Going downward (initial velocity is zero; free-fall):
$h = \frac{1}{2}gt^2$

$h = \frac{1}{2}(32.2)(5^2)$

$h = 402.5 \, \text{ ft}$           answer