$\Sigma M_G = 0$
$3F_{DF} = 4(210)$
$F_{DF} = 280 ~ \text{kN}$ compression answer
$\Sigma F_V = 0$
$\frac{3}{5}F_{DG} + 120 = 210$
$F_{DG} = 150 ~ \text{kN}$ compression answer
$\Sigma M_D = 0$
$3F_{EG} + 4(120) = 8(210)$
$F_{EG} = 400 ~ \text{kN}$ tension answer