**Problem 417**

Using the method of sections, determine the force in members BD, CD, and CE of the roof truss shown in Fig. P-417.

**Solution 417**

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$\Sigma M_F = 0$

$12R_A = 4(360)$

$R_A = 120 \, \text{kN}$

$\Sigma M_C = 0$

$3F_{BD} = 4(120)$

$F_{BD} = 160 \, \text{kN}$ compression *answer*

$\Sigma F_V = 0$

$\frac{3}{5}F_{CD} = 120$

$F_{CD} = 200 \, \text{kN}$ compression *answer*

$\Sigma M_D = 0$

$3F_{CE} = 8(120)$

$F_{CE} = 320 \, \text{kN}$ tension *answer*