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Analysis of Structures
- Method of Joints | Analysis of Simple Trusses
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Method of Sections | Analysis of Simple Trusses
- Problem 001-ms | Method of Sections
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- Problem 004-ms | Method of Sections
- Problem 005-ms | Method of Sections
- Problem 417 - Roof Truss by Method of Sections
- Problem 418 - Warren Truss by Method of Sections
- Problem 419 - Warren Truss by Method of Sections
- Problem 420 - Howe Truss by Method of Sections
- Problem 421 - Cantilever Truss by Method of Sections
- Problem 422 - Right-triangular Truss by Method of Sections
- Problem 423 - Howe Roof Truss by Method of Sections
- Problem 424 - Method of Joints Checked by Method of Sections
- Problem 425 - Fink Truss by Method of Sections
- Problem 426 - Fink Truss by Method of Sections
- Problem 427 - Interior Members of Nacelle Truss by Method of Sections
- Problem 428 - Howe Truss by Method of Sections
- Problem 429 - Cantilever Truss by Method of Sections
- Problem 430 - Parker Truss by Method of Sections
- Problem 431 - Members in the Third Panel of a Parker Truss
- Problem 432 - Force in Members of a Truss by Method of Sections
- Problem 433 - Scissors Truss by Method of Sections
- Problem 434 - Scissors Truss by Method of Sections
- Problem 435 - Transmission Tower by Method of Sections
- Problem 436 - Howe Truss With Counter Braces
- Problem 437 - Truss With Counter Diagonals
- Problem 438 - Truss With Redundant Members
- Method of Members | Frames Containing Three-Force Members
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How did it came up with 4&3
How did it came up with 4&3 instead of 0.75m and 1m?
0.75/1 = 3/4
In reply to How did it came up with 4&3 by Han (not verified)
0.75/1 = 3/4
The right-angled triangle 1,0
In reply to How did it came up with 4&3 by Han (not verified)
The right-angled triangle 1,0.75,1.25
We can multiple them with 4 just to get sine and cosine
Then the sides are 4,3,5 so that we can get sin,cos