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Solution to Problem 653 | Deflections in Simply Supported Beams

Problem 653
Compute the midspan value of EIδ for the beam shown in Fig. P-653. (Hint: Draw the M diagram by parts, starting from midspan toward the ends. Also take advantage of symmetry to note that the tangent drawn to the elastic curve at midspan is horizontal.)
 

Simple beam with symmetrically placed rectangular load

 

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Deflections in Simply Supported Beams | Area-Moment Method

The deflection δ at some point B of a simply supported beam can be obtained by the following steps:
 

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Components of a Force

Forces acting at some angle from the the coordinate axes can be resolved into mutually perpendicular forces called components. The component of a force parallel to the x-axis is called the x-component, parallel to y-axis the y-component, and so on.
 

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Resultant of Parallel Force System

Coplanar Parallel Force System
Parallel forces can be in the same or in opposite directions. The sign of the direction can be chosen arbitrarily, meaning, taking one direction as positive makes the opposite direction negative. The complete definition of the resultant is according to its magnitude, direction, and line of action.
 

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Resultant of Concurrent Force System

Resultant of a force system is a force or a couple that will have the same effect to the body, both in translation and rotation, if all the forces are removed and replaced by the resultant.
 

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06 Area Within the Curve r^2 = 16 cos θ

Example 6
What is the area within the curve r2 = 16 cos θ?
 

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05 Area Enclosed by Four-Leaved Rose r = a cos 2θ

Find the area enclosed by four-leaved rose r = a cos 2θ.
 

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04 Area of the Inner Loop of the Limacon r = a(1 + 2 cos θ)

Example 4
Find the area of the inner loop of the limacon r = a(1 + 2 cos θ).
 

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03 Area Inside the Cardioid r = a(1 + cos θ) but Outside the Circle r = a

Example 3
Find the area inside the cardioid r = a(1 + cos θ) but outside the circle r = a.
 

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Example 6 | Plane Areas in Rectangular Coordinates

Example 6
Find each of the two areas bounded by the curves y = x3 - 4x and y = x2 + 2x.
 

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