Date of Exam May 1998 Subject Mathematics, Surveying and Transportation Engineering Problem Find the slope of the curve $x^2 + y^2 - 6x + 10y + 5 = 0$ at point $(1, \, 0)$. A. 2/5 C. -5/2 B. 1/4 D. 2 Answer Key Click here to show or hide the answer key [ A ] Solution Click here to expand or collapse this section $x^2 + y^2 - 6x + 10y + 5 = 0$ $2x + 2y \, y' - 6 + 10y' = 0$ At (1, 0) $2(1) + 2(0) \, y' - 6 + 10y' = 0$ $y' = 2/5$ Category Differential Calculus Slope of the Curve Log in or register to post comments
