$x = t^2 + 2t$

$dx = (2t + 2) \, dt$

$y = 2t^3 - 6t$

$dy = (6t^2 - 6) \, dt$

$\dfrac{dy}{dx} = \dfrac{(6t^2 - 6)\,dt}{(2t + 2)\,dt}$

$\dfrac{dy}{dx} = \dfrac{3t^2 - 3}{t + 1}$

When *t* = 0, *dy*/*dx* = -3

When *t* = 2, *dy*/*dx* = 3

When *t* = 5, *dy*/*dx* = 12

Answer: [ D ]