Problem A tensile load of 8000 kg elongates a 1-m long square rod by 1 mm. Steel modulus of elasticity is 2 × 10^{6} kg/cm^{2}. What is the dimension of a side of the rod?

Answer Key

Solution

$0.1 = \dfrac{8,000(100)}{x^2 (2 \times 10^6)}$

$x^2 = 4$

$x = 2 ~ \text{cm}$ ← Answer: [ C ]

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