Uniformly Distributed Load

Problem 653 | Beam Deflection by Conjugate Beam Method

Problem 653
Compute the midspan value of EIδ for the beam shown in Fig. P-653. (Hint: Draw the M diagram by parts, starting from midspan toward the ends. Also take advantage of symmetry.
 

653-conjugate-beam-method.gif

 

Problem 332 | Equilibrium of Parallel Force System

Problem 332
Determine the reactions for the beam shown in Fig. P-332.
 

332-beam-reaction.gif

 

Solution to Problem 692 | Beam Deflection by Method of Superposition

Problem 692
Find the value of EIδ midway between the supports for the beam shown in Fig. P-692. (Hint: Combine Case No. 11 and one half of Case No. 8.)
 

Solution to Problem 691 | Beam Deflection by Method of Superposition

Problem 691
Determine the midspan deflection for the beam shown in Fig. P-691. (Hint: Apply Case No. 7 and integrate.)
 

Solution to Problem 689 | Beam Deflection by Method of Superposition

Problem 689
The beam shown in Fig. P-689 has a rectangular cross section 4 inches wide by 8 inches deep. Compute the value of P that will limit the midspan deflection to 0.5 inch. Use E = 1.5 × 106 psi.

Solution to Problem 688 | Beam Deflection by Method of Superposition

Problem 688
Determine the midspan value of EIδ at the left end of the beam shown in Fig. P-688.
 

Solution to Problem 687 | Beam Deflection by Method of Superposition

Problem 687
Determine the midspan deflection of the beam shown in Fig. P-687 if E = 10 GPa and I = 20 × 106 mm4.
 

Solution to Problem 681 | Midspan Deflection

Problem 681
Show that the midspan value of EIδ is (wob/48)(L3 - 2Lb2 + b3) for the beam in part (a) of Fig. P-681. Then use this result to find the midspan EIδ of the loading in part (b) by assuming the loading to exceed over two separate intervals that start from midspan and adding the results.
 

Solution to Problem 669 | Deflections in Simply Supported Beams

Problem 669
Compute the value of EIδ midway between the supports of the beam shown in Fig. P-669.
 

Overhang beam with uniform loads between supports and at the overhang

 

Pages

Subscribe to RSS - Uniformly Distributed Load