Solution to Problem 437 | Relationship Between Load, Shear, and Moment Problem 437 Cantilever beam loaded as shown in Fig. P-437. Click here to read or hide the general instruction Without writing shear and moment equations, draw the shear and moment diagrams for the beams specified in the following problems. Give numerical values at all change of loading positions and at all points of zero shear. Solution 437 Click here to expand or collapse this section To draw the Shear Diagram V_{A} = -1000 lb V_{B} = V_{A} + Area in load diagram V_{B} = -1000 + 0 = -1000 lb V_{B2} = V_{B} + 500 = -1000 + 500 V_{B2} = -500 lb V_{C} = V_{B2} + Area in load diagram V_{C} = -500 + 0 = -500 lb V_{D} = V_{C} + Area in load diagram V_{D} = -500 - 400(4) = -2100 lb To draw the Moment Diagram M_{A} = 0 M_{B} = M_{A} + Area in shear diagram M_{B} = 0 - 1000(2) = -2000 lb·ft M_{C} = M_{B} + Area in shear diagram M_{C} = -2000 - 500(2) = -3000 lb·ft M_{D} = M_{C} + Area in shear diagram M_{D} = -3000 - ½ (500 + 2100)(4) M_{D} = -8200 lb·ft Tags concentrated load Uniformly Distributed Load cantilever beam relationship between load shear and moment Log in or register to post comments Book traversal links for Solution to Problem 437 | Relationship Between Load, Shear, and Moment Solution to Problem 436 | Relationship Between Load, Shear, and Moment Up Solution to Problem 438 | Relationship Between Load, Shear, and Moment