Relevant data extracted from Solution 918
Area=60 in.2
The largest tensile stress is at corner B
σB=320 psi
Additional compression force P2 for zero stress at corner B
σB=320−P260=0
P2=19,200 lbs ← answer
Stress at each corner from Solution 918
σA=−480 psi
σB=320 psi
σC=80 psi
σD=−720 psi
Stress at each corner due to additional stress σ2 = -320 psi.
σA=−480−320=−800 psi
σB=320−320=0
σC=80−320=−240 psi
σD=−720−320=−1040 psi
See figure above.