Combined Axial and Bending

Combined axial compression and bending
σ=PA±McI
 

Combined axial tension and bending
σ=PA±McI
 

For the flexure quantity Mc/I, use (+) for fibers in tension and (-) for fibers in compression.
 

Problem 902
Compare the maximum stress in bent rod 1/2 in. square, where the load P is 1/2 in. off center as shown in Figure P-902, with the maximum stress if the rod were straight and the load applied axially.
 

902-bar-in-eccentric-compression.gif

 

Solution 902
For P applied off-center:

The most stressed are the bottom fibers, it is subjected to compression due to axial load and compression due to bending.
σ=PA6Mbd2

σ=P0.526(0.5P)0.5(0.52)

σ=28P

 

For P applied axially:

σ=PA

σ=P0.52

σ=4P

 

Ratio=28P4P

Ratio=71       answer