Problem 23 It is desired to cut off a piece of lead pipe 2 in. in outside diameter and 1/4 in. thick, so that it will melt into a cube of edge 4 in. How long a piece will be required?

Solution 23

r = inner radius of pipe $r = R - \frac{1}{4} = 0.75 ~ \text{in.}$

Volume of pipe = Volume of cube $\pi (1^2 - 0.75^2)L = 4^3$

$L = 46.564 ~ \text{in.}$ answer

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