**Problem 236**

A parallel force system acts on the lever shown in Fig. P-236. Determine the magnitude and position of the resultant.

**Solution 236**

## Click here to show or hide the solution

$R = \Sigma F$

$R = 30 + 60 - 20 + 40$

$R = 110 \, \text{ lb}$ downward

$M_A = \Sigma xF$

$M_A = 2(30) + 5(60) - 7(20) + 11(40)$

$M_A = 660 \, \text{ ft}\cdot\text{lb}$ clockwise

$Rd = M_A$

$110d = 660$

$d = 6 \, \text{ ft}$ to the right of A

Thus, R = 110 lb downward at 6 ft to the right of A. *answer*