$R = \Sigma F$
$R = 30 + 60 - 20 + 40$
$R = 110 \, \text{ lb}$ downward
$M_A = \Sigma xF$
$M_A = 2(30) + 5(60) - 7(20) + 11(40)$
$M_A = 660 \, \text{ ft}\cdot\text{lb}$ clockwise
$Rd = M_A$
$110d = 660$
$d = 6 \, \text{ ft}$ to the right of A
Thus, R = 110 lb downward at 6 ft to the right of A. answer