Rate of Benjie
$v_B = \dfrac{400}{65} = \dfrac{80}{13}$
Rate of Jerwin
$v_J = \dfrac{400}{t}$
Benjie and Jerwin run a total of 400 m in 35 seconds
$s_B + s_J = 400$
$\left( \dfrac{80}{13} \right)(35) + \left( \dfrac{400}{t} \right)(35) = 400$
$\dfrac{7}{13} + \dfrac{35}{t} = 1$
$\dfrac{35}{t} = \dfrac{6}{13}$
$t = 75.83 ~ \text{sec}$ answer