$\Sigma M_A = 0$
$4R_E = 6(120)$
$R_E = 180 \, \text{ kN}$ answer
$\Sigma F_H = 0$
$A_H = R_E$
$A_H = 180 \, \text{ kN}$ answer
$\Sigma F_V = 0$
$A_V = 120 \, \text{ kN}$ answer
$\Sigma M_A = 0$
$3(\frac{2}{\sqrt{13}}F_{BD}) = 6(120)$
$F_{BD} = 432.67 \, \text{ kN}$ answer